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Created by Dr. Xi on March 22, 2013 12:18:39    Last update: March 22, 2013 12:18:39
This is a step-by-step guide to create a "contract-first" web service with Apache CXF. It's a lot easier than doing the same thing with Spring-WS. The project uses standard Maven directory layout. Define the data types ( src/main/resources/hello.xsd ): <xs:schema xmlns:xs="http://www.w3.org/200... Define the service ( src/main/resources/hello.wsdl ): <?xml version='1.1' encoding='UTF-8'?> <wsdl:de... Create pom.xml : <project xmlns="http://maven.apache.org/POM/4.... Generate jaxb bindings: $ mvn generate-sources Code the web service ( src/main/java/com/example/cxfdemo/HelloPortImpl.java ): package com.example.cxfdemo; import javax.j... Declare the CXF servlet in web.xml ( src/main/webapp/WEB-INF/web.xml ): <?xml version="1.0" encoding="UTF-8"?> <web-app... Wire up the web service implementation ( src/main/webapp/WEB-INF/cxf-servlet.xml ): <?xml version="1.0" encoding="UTF-8"?> <beans x... Build the WAR: $ mvn clean package After the webapp is deployed (Tomcat running on port 8080), the web service (WSDL) is available via...
Created by nogeek on December 29, 2011 13:31:44    Last update: December 29, 2011 14:29:13
Tomcat allows you to create multiple server instances for the same installation. The installation directory is identified as CATALINA_HOME , the instance directory is identified as CATALINA_BASE . Here are the steps: Create a base directory for the new instance, for example: /home/nogeek/tomcat1 . Create the subdirectories: mkdir -p /home/nogeek/tomcat/{bin,conf,logs,temp,w... Copy web.xml from the installation directory: cp $CATALINA_HOME/conf/web.xml /home/nogeek/tomcat... Copy logging.properties from the installation directory: cp $CATALINA_HOME/conf/logging.properties /home/no... Create server.xml under tomcat1/conf : <?xml version='1.0' encoding='utf-8'?> <Server ... Create script setenv.sh under tomcat1/bin : # Edit this file to set custom options # Tomcat... Copy startup.sh and shutdown.sh from the installation directory. Add the following two lines to the beginning of each: CATALINA_BASE=/home/nogeek/tomcat1 export CATAL... Create a soft link for catalina.sh in tomcat1/bin : $ ln -s ~/apache-tomcat-7.0.22/bin/catalina.sh cat...
Created by nogeek on November 17, 2011 14:30:28    Last update: November 17, 2011 14:30:28
CATALINA_HOME is the root directory where Tomcat is installed. CATALINA_BASE is the same as CATALINA_HOME for single instance Tomcat configuration. For multiple instance configurations CATALINA_BASE is the root of that instance. The startup script prints out the values of CATALINA_HOME and CATALINA_BASE at startup: Using CATALINA_BASE: "C:\Apps\tomcat-7.0.22" ...
Created by freyo on August 17, 2011 12:29:46    Last update: August 17, 2011 12:29:46
In Android.mk , you can define LOCAL_JARJAR_RULES like this: LOCAL_JARJAR_RULES := $(LOCAL_PATH)/jarjar-rules.t... and in jarjar-rules.txt define a rule like this: rule org.bouncycastle.** com.android.@0 The build will change all org.bouncycastle to com.android.org.bouncycastle . Therefore, in your classes which are dependent on the library produced, the import statements should look like: import com.android.org.bouncycastle... Help for the jarjar utility (in prebuilt/common/jarjar/ ): $ java -jar jarjar-1.0rc8.jar Jar Jar Links - ...
Created by Dr. Xi on January 14, 2010 00:28:27    Last update: March 30, 2011 15:37:44
A task that a Java developer does so frequently is to find out where a certain class can be found - to resolve compilation errors, classpath issues, or version conflicts of the same class introduced by multiple class loaders. A long while back I wrote a simple Perl script to perform the task. Later I was informed that there are Swing based Jar Browser and Jars Browser . Then, there are a couple of shell one-liners: # one liner 1 find -name "*.jar" -print0 | xarg... But all of them share the same problem: if a class is in a jar nested in another jar, it cannot be found. Such is the case for a class inside a jar under the WEB-INF/lib directory of a...
Created by Fang on August 13, 2009 03:32:36    Last update: January 09, 2010 21:34:34
Maven asks you to organize your project by a standard directory layout. Although you can override the proposed structure via the project descriptor , conformance is strongly recommended. At the top level there are only two directories: src and target . The target directory is used to house all output of the build. The src directory contains all of the source material for building the project, its site and so on. The src directory contains a subdirectory for each type of resources: main for the main build artifact test for the unit test code site for your project site's documentation This is the general layout: Directory Description LICENSE.tx t Project's license README.txt Project's readme pom.xml The Maven "Project Object Model" src/main/java under which the normal...
Created by Fang on September 07, 2009 16:39:37    Last update: September 07, 2009 18:43:04
It's easiest to use the archetype plugin to start a new Maven project. I'll use struts 1 as example since it's not in the built-in archetypes for archetype:generate . Generate a simple webapp with archetype:generate : C:\work\maven>mvn archetype:generate -DarchetypeAr... It generates a directory structure like this: struts1app struts1app/pom.xml struts1app/src... with a simple POM: <project xmlns="http://maven.apache.org/POM/4.0.0"... Create settings.xml in $HOME/.m2 , add Java.net repository for Java EE dependencies: <?xml version="1.0" encoding="UTF-8"?> <setting... Add Java EE and Struts dependencies in pom.xml . Note that the Java EE dependency has scope provided , meaning that the web app container provides the jars, therefore we don't need to bundle them with our war fie. <project xmlns="http://maven.apache.org/POM/4.0.0"... Create a directory named java under main , create the Struts form and...
Created by Dr. Xi on September 04, 2008 18:18:07    Last update: September 04, 2008 18:18:07
If the argument to getResourceAsStream is a directory, the stream content returns a list of files under that directory. The following code returns the list of files under the first directory on CLASSPATH (not the current directory): import java.io.*; public class TestGetResou...
Created by Dr. Xi on August 10, 2007 19:53:32    Last update: August 10, 2007 19:53:32
As a Java developer, I often need to find out which Jar file to include on my classpath in order to fix some compilation error (undefined package, class etc). This is a little Perl script I wrote to facilitate this task. #!/bin/perl # find jar containing specified...