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Created by Fang on January 10, 2014 14:07:20    Last update: January 10, 2014 14:07:20
An example project with Spring MVC and Apache Tiles. List of files: ./pom.xml ./src/main/webapp/WEB-INF/web.xml... ./pom.xml : <?xml version="1.0" encoding="UTF-8"?> <pro... ./src/main/webapp/WEB-INF/web.xml : <?xml version="1.0" encoding="UTF-8"?> <web-app... ./src/main/webapp/WEB-INF/applicationContext.xml : <?xml version="1.0" encoding="UTF-8"?> <beans x... ./src/main/webapp/WEB-INF/spring-servlet.xml : <?xml version="1.0" encoding="UTF-8"?> <beans x... ./src/main/webapp/WEB-INF/tiles-definitions.xml : <?xml version="1.0" encoding="UTF-8"?> <!DOCTYP... ./src/main/webapp/WEB-INF/jsp/template.jsp : <!DOCTYPE html> <%@ page pageEncoding="UTF-8" %... ./src/main/java/com/example/MyController.java : package com.example; import javax.servlet.S...
Created by Dr. Xi on September 18, 2013 19:54:58    Last update: September 18, 2013 19:54:58
You can define a JDBC datasource in $CATALINA_BASE/conf/server.xml under <GlobalNamingResources> like this: <GlobalNamingResources> <Resource name="jd... But you will not be able to lookup the datasource in your webapp, unless you define a link in your per-web-application JNDI context (for example, META-INF/context.xml ): <?xml version="1.0"?> <Context> <Resourc... By tomcat documentation : The GlobalNamingResources element defines the global JNDI resources for the Server. These resources are listed in the server's global JNDI resource context. This context is distinct from the per-web-application JNDI contexts described in the JNDI Resources HOW-TO . The resources defined in this element are not visible in the per-web-application contexts unless you explicitly link them with <ResourceLink> elements.
Created by Dr. Xi on March 22, 2013 12:18:39    Last update: March 22, 2013 12:18:39
This is a step-by-step guide to create a "contract-first" web service with Apache CXF. It's a lot easier than doing the same thing with Spring-WS. The project uses standard Maven directory layout. Define the data types ( src/main/resources/hello.xsd ): <xs:schema xmlns:xs="http://www.w3.org/200... Define the service ( src/main/resources/hello.wsdl ): <?xml version='1.1' encoding='UTF-8'?> <wsdl:de... Create pom.xml : <project xmlns="http://maven.apache.org/POM/4.... Generate jaxb bindings: $ mvn generate-sources Code the web service ( src/main/java/com/example/cxfdemo/HelloPortImpl.java ): package com.example.cxfdemo; import javax.j... Declare the CXF servlet in web.xml ( src/main/webapp/WEB-INF/web.xml ): <?xml version="1.0" encoding="UTF-8"?> <web-app... Wire up the web service implementation ( src/main/webapp/WEB-INF/cxf-servlet.xml ): <?xml version="1.0" encoding="UTF-8"?> <beans x... Build the WAR: $ mvn clean package After the webapp is deployed (Tomcat running on port 8080), the web service (WSDL) is available via...
Created by Dr. Xi on March 21, 2013 20:29:14    Last update: March 22, 2013 08:58:08
Spring-WS documentation says you can use a Jaxb object as parameter or return type, provided that it is annotated with javax.xml.bind.annotation.XmlRootElement , or is an instance of javax.xml.bind.JAXBElement . But that's a lot easier said than done! For example, if sayHelloResponse is defined as: <xs:element name="sayHelloResponse" type="tns:sayH... then the JAXB generated class is not annotated with XmlRootElement , therefore, unusable for Spring-WS. You have to define the type as: <xs:element name="sayHelloResponse"> <xs:compl... in order to generate a type annotated with XmlRootElement . But that is not always possible. Alternatively, you can use the Maven plugin maven-jaxb2-plugin with the jaxb2-basics-annotate plugin (yes, plugin inside plugin) to inject the XmlRootElement annotation into the generated JAXB class. This is the pom: <project xmlns="http://maven.apache.org/POM/4.0.0"... and the binding file: <?xml version="1.0" encoding="UTF-8" standalone="y......
Created by Dr. Xi on March 07, 2013 20:26:23    Last update: March 07, 2013 20:26:23
Create a jax-ws web service with Spring, Apache CXF and Maven. Create the pom.xml : <project xmlns="http://maven.apache.org/POM/4.0.0"... Create the web service interface ( src/main/java/jaxws/JaxwsHello.java ): package jaxws; import javax.jws.WebService;... Implement the web service ( src/main/java/jaxws/JaxwsHelloImpl.java ): package jaxws; import javax.jws.WebService;... Create src/main/webapp/WEB-INF/cxf-servlet.xml : <?xml version="1.0" encoding="UTF-8"?> <beans x... Register the CXF servlet in src/main/webapp/WEB-INF/web.xml : <?xml version="1.0" encoding="UTF-8"?> <web-app... Build: mvn package The resulting WAR file can be deployed to any servlet container (for example, Tomcat).
Created by Dr. Xi on March 01, 2013 16:09:00    Last update: March 04, 2013 12:28:23
This is probably the easiest way to create a web service in JAX-WS. There are no external dependencies other than Java EE. Assuming that you build the web service as a webapp (say jaxws-example.war), the pom.xml can be as simple as: <project xmlns="http://maven.apache.org/POM/4.0.0"... You can implement and deploy the web service in 3 easy steps: Code the service as a POJO (annotate class to expose it as a web service) package jaxws; import javax.jws.WebMethod; ... Declare the POJO as a servlet in WEB-INF/web.xml : <?xml version="1.0" encoding="UTF-8"?> <web-app... Build the webapp, and deploy the resulting war: mvn package The only catch is, this only works for a Java EE 5+ compliant container such as WebLogic or JBoss. It does not work for a simple servlet...
Created by Fang on January 04, 2013 09:02:44    Last update: January 04, 2013 09:02:44
This snippet sets system properties from Maven surefire test plugin. This is useful when you want to set logging (for example, log4j) properties based on Maven project properties. Example that sets system property testlog.dir : <plugins> <plugin> <groupId>org.apach... Example log4j.xml that uses system property testlog.dir : <?xml version="1.0" encoding="UTF-8"?> <!DOCTYP...
Created by Dr. Xi on April 19, 2012 10:10:08    Last update: April 19, 2012 10:11:06
The default servlet for Tomcat is declared in $CATALINA_HOME/conf/web.xml : <servlet> <servlet-name>default</servle... Therefore, static content is rendered by the default configuration unless you override it with your own definitions. If you want to allow directory listing, just change the listing parameter to true : <init-param> <param-name>listings</para... Change the welcome-file-list to display a default page in lieu of a directory listing: <welcome-file-list> <welcome-file>home.xhtml</... Welcome pages are defined at the Web application level.
Created by Fang on March 05, 2012 20:11:56    Last update: March 05, 2012 20:11:56
This is a bare bones Maven project to get started with Java JSR 303 bean validation. Directory structure: ./pom.xml ./src ./src/main ./src/main/jav... pom.xml : <project xmlns="http://maven.apache.org/POM/4.0.0"... which includes dependencies on JUnit, Java bean validation API and the Hibernate validator reference implementation.
Created by Fang on January 31, 2012 15:40:34    Last update: January 31, 2012 15:41:28
This is a simple Hello World application with Spring 3 MVC. Like the default Apache HTTPd welcome page, it displays " It works! " when successfully deployed. The sole purpose is to show the minimum elements needed to setup Spring 3 MVC. I use Maven since it's so much easier than downloading the dependencies manually. Directory layout: ./src ./src/main ./src/main/webapp ./src/... pom.xml : <?xml version="1.0" encoding="UTF-8"?> <project... WEB-INF/web.xml : <?xml version="1.0" encoding="UTF-8"?> <web-app... WEB-INF/applicationContext.xml (empty, but needed): <?xml version="1.0" encoding="UTF-8"?> <beans x... WEB-INF/spring-servlet.xml : <?xml version="1.0" encoding="UTF-8"?> <beans x... WEB-INF/jsp/home.jsp : <!DOCTYPE html> <html> <head> <title>H... Build with: mvn clean package The resulting webapp is target/springmvc.war .
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